Question

I have the following code that should select all the users in the relevant table in my database:

$hof = mysql_query("SELECT * FROM users");

$name = array();
$website = array();
$i=0;
while($result = mysql_fetch_array($hof)){
$name[$i] = $result['company']; 
$website[$i] = $result['website'];
}
$i++;

I want to echo out the names and websites of all in the html section of my script (below the php) which will be a Hall of Frame of sorts. How would i do is? The fact that i do not know the size of the array deters me.

Usually, if i knew the size, i would so something like:

<?php echo $name[1];?>
<?php echo $name[2];?>
//and so on

Many thanks in advance. P.S. I plan to move across to MySQLi when i have the functionality of the website sorted first on localhost. Cheers

Answer 1

Your $i++; statement should be inside while loop

while($result = mysql_fetch_array($hof)){
    $name[$i] = $result['company']; 
    $website[$i] = $result['website'];
    $i++;
}

Better You do it like this,

$rows = array();
while($result = mysql_fetch_assoc($hof)){
        $rows[] = $result; 
}

and you echo them like this,

<?php
$len = count($name);
for($i=0;$i<$len;$i++){
    echo $name[1];
}
?>

And for the alternative method use this,

<?php
foreach($rows as $row){
    echo $row['name']; // use $row['website'] to echo website.
}
?>