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Home/ Questions/Q 575729
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Editorial Team
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Editorial Team
Asked: May 13, 20262026-05-13T13:58:18+00:00 2026-05-13T13:58:18+00:00

I have the following code that works: <script type=text/javascript> $(document).ready(function() { // Initialise the

  • 0

I have the following code that works:

<script type="text/javascript">
     $(document).ready(function() {
    // Initialise the table
    $('#table_1').tableDnD({
     onDrop: function(table, row) {
    $.tableDnD.serialize();

    location.href="test.php?" + $.tableDnD.serialize();
    }
 });

});
</script>

And it sends through a refresh location.href all the data to the following script:

<?php
$table_1[] = $_GET['table_1'];
$i = 0;
if(!empty($table_1[0])){
    foreach($table_1 as $value) {
        foreach($value as $row){
            $i++;
            mysql_query("UPDATE mytable SET tableOrder='$i' WHERE id = '$row'");
        }
    }
}

?>

What I’d like to do is send the data using ajax, and this is what I have so far, but it’s not working:

<script type="text/javascript">
    $(document).ready(function() {
    // Initialise the table
    $('#table_1').tableDnD({
    onDrop: function(table, row) {
     $.tableDnD.serialize();

    $.ajax({
        type: "GET",
        url: "test.php",
        data: "?"+$.tableDnD.serialize(),
        success: function(html){
            alert("Eureka!");
        }
    });

        }
    });

});
</script>
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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-13T13:58:18+00:00Added an answer on May 13, 2026 at 1:58 pm

    change type to “POST” and lose the question mark in data

    OR

    remove data and concat what you have in data with url

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