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Home/ Questions/Q 6211697
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Editorial Team
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Editorial Team
Asked: May 24, 20262026-05-24T06:23:00+00:00 2026-05-24T06:23:00+00:00

I have the following code thats supposed to take the input entered into a

  • 0

I have the following code thats supposed to take the input entered into a UITextField and validate it. It doesn’t seem to be working and Im a little confused as to why.

Could someone give me some advice please?

NSString *const regularExpression = @"([0-9a-zA-Z\\s]{1,6})";
NSError *error = NULL;
NSRegularExpression *regex = [NSRegularExpression regularExpressionWithPattern:regularExpression options:NSRegularExpressionCaseInsensitive error:&error];

           if (error) 
              {
               NSLog(@"error %@", error);
              }

NSUInteger numberOfMatches = 
[regex numberOfMatchesInString:s                                   options:0                                                 range:NSMakeRange(0, [s length])];
NSLog(@"index = %d", i);
NSLog(@"Value of TextField = %@", s);
NSLog(@"Regular expression is = %@", regularExpression);
if (numberOfMatches <= 0)
  {
   NSLog(@"Failed regex test ");
  }

This string should fail the regular expression test :”Einxnkxkd Xnckck”

But it passed.

im not sure how and why…
Anything obvious Im missing here?
Thanks

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  1. Editorial Team
    Editorial Team
    2026-05-24T06:23:01+00:00Added an answer on May 24, 2026 at 6:23 am

    The method numberOfMatchesInString: searches for matches within the string. It does not test your pattern against the entire string.

    It is passing because the pattern ([0-9a-zA-Z\\s]{1,6}) is matching at least the first six letters of your test string Einxnkxkd Xnckck yielding Einxnk. In fact, I can find lots of matches: E, Ein, inx, etc.

    If you want to make sure the whole string matches the pattern, use ^ to indicate the beginning of the string and $ to mark the end of it, so that your pattern becomes ^([0-9a-zA-Z\\s]{1,6})$.

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