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Home/ Questions/Q 6250645
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Editorial Team
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Editorial Team
Asked: May 24, 20262026-05-24T13:27:50+00:00 2026-05-24T13:27:50+00:00

I have the following code: typedef unsigned char some_type[6]; int main() { some_type some_var1;

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I have the following code:

typedef unsigned char some_type[6];

int main() {
        some_type some_var1;
        some_type some_var2;
        some_var1 = some_var2;
        return 0;
}

And when i try to compile it, I get the following error message:

incompatible types when assigning to type 'some_type' from type 'unsigned char *'

Why is this? Both variables are exactly the same type? What can I do to make it work? I can’t change the typedef, as it is part of an API I am using.

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-24T13:27:52+00:00Added an answer on May 24, 2026 at 1:27 pm

    You can’t assign arrays to each other like that. If these are strings, use strcpy:

    strcpy(some_var1, some_var2);
    

    If not, use memcpy:

    memcpy(&some_var1, &some_var2, sizeof (some_type));
    
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