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Home/ Questions/Q 7601757
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Editorial Team
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Editorial Team
Asked: May 30, 20262026-05-30T23:14:30+00:00 2026-05-30T23:14:30+00:00

I have the following code: var htmlname=”; var names = result.names $.each(names, function( i,

  • 0

I have the following code:

            var htmlname='';
            var names = result.names
            $.each(names, function( i, name){

               htmlname = "<td>" + name + "</td>";

               $('#adminall tr:last').html(htmlname);

                var row = document.createElement('tr');
                var tableCurrentPoints = document.getElementById("adminall"); // find table to append to
                tableCurrentPoints.appendChild(row); // append row to table


            });


            var htmlemail='';
            var emails = result.emails
            $.each(emails, function( ii, email){

               htmlemail = "<td>" + email + "</td>";

               $('#adminall tr:last').html(htmlemail);

                var row = document.createElement('tr');
                var tableCurrentPoints = document.getElementById("adminall"); // find table to append to
                tableCurrentPoints.appendChild(row); // append row to table


            });

And then the table which its appending too:

        <table id="adminall" style="margin:10px 0px 0px 0px;" width="100%" border="0" cellpadding="0" cellspacing="0">
        <tr id="adminallheader">

        </tr>
        <tr></tr>

    </table>

This is from a success handler within an AJAX request. I am attempting to create a table populated with the data from the query, and I’m guessing it should be created in Javascript as I am attempting here, but I can’t get it to work. At the moment it has all the data (name and email) in one column, but it needs to be split across the two.

Any ideas?

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-30T23:14:31+00:00Added an answer on May 30, 2026 at 11:14 pm

    You should do something like

           var names = result.names
           $.each(names, function( i, name){
               //get the corrsponding email
               var email = result.emails[i];
               var htmlname = "<td>" + name + "</td><td>"+email"</td>";
    
               $('#adminall tr:last').append(htmlname);
    
                var row = document.createElement('tr');
                var tableCurrentPoints = document.getElementById("adminall"); // find table to append to
                tableCurrentPoints.appendChild(row); // append row to table
    
    
            });
    

    and loop only once and not twice.

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