Question

I have the following code. What I have labelled block 1 and block 2 don’t seem to work together but one does if i get rid of the other; when checking using print_r. I am fairly new to php and was wondering if somebody could point out where I went wrong. I had it working somewhere else before but lost the file. Many thanks in advance.

P.S: I am aware it is a good idea to get into PDO and mysqli sooner rather than later. But I just want to get to grips with the basics first.

<?php


//Connect to database

$connect = mysql_connect ("localhost","root","password");
$db = mysql_select_db("project");


//Find top 100 most popular images

$pop = mysql_query("


SELECT * FROM users ORDER BY pop DESC LIMIT 2

");

//Define local variables for images to show

//block 1//

$images = array();
while ($row = mysql_fetch_array($pop)) {
    $images[] = $row['image'];
    }

//block2//

$links = array ();
while ($row = mysql_fetch_array($pop)){
$links[] = $row['username'];
}

?>

Answer 1

mysql_data_seek will work:

$images = array();
while ($row = mysql_fetch_array($pop)) {
    $images[] = $row['image'];
}

mysql_data_seek( $pop, 0 );

$links = array ();
while ($row = mysql_fetch_array($pop)){
    $links[] = $row['username'];
}

However, a better / cleaner solution to your problem would be to put both values into their respective arrays during the first loop:

$links = array();
$images = array();
while ($row = mysql_fetch_assoc($pop)) {
    $images[] = $row['image'];
    $links[] = $row['username'];
}

Or, even cleaner – add an array to your array:

$avatars = array();
while ($row = mysql_fetch_assoc($pop)) {
    array_push(
        $avatars, 
        array('image' => $row['image'], 'username' => $row['username'])
    );
}

var_dump($avatars);