Question

I have the following code which displays a dialog box to the user if no network connection is detected.

private void createNoNetworkDialog() {

    LayoutInflater inflater = LayoutInflater.from(this);
    AlertDialog.Builder builder = new AlertDialog.Builder(this);
    View view = inflater.inflate(R.layout.offline_mode_dialog,null);
    builder.setView(view);
    builder.show();

}

There are two buttons in this dialog which have methods defined for their onClick actions. I would like to close the dialog pop-up after either of these button is pressed. Any ideas??

Answer 1

Yes,call dismiss() from the Listener‘s onClick since the DialogInterface reference is passed, which allows for dismissal.

Eg

builder.setPositiveButton ("Yes", new DialogInterface.OnClickListener()
                             {
  public void onClick (DialogInterface dialog, int which)
  {
    //do stuff beforehand
    dialog.dismiss();
  }
});

Or if your buttons are inside the layout, show the dialog and keep a reference to it (final AlertDialog dialog = builder.show()). Then use dialog.findViewById() to find the respective buttons. Assign a normal View.OnClickListener and in it call dismiss() using the dialog reference you’re holding.