Question

I have the following code which i want to display the picture not the path. It is on php and
I’m getting the path from a database. I know how to do it on html but not on php

this is my code

  echo"<th>ImagePath:</th> <td>".$row['imgPath'] . " </td></tr>";

how can i convert it so it shows the image and not the path? and make the heigh and width like 200
Any help is appreciated. thanks

Answer 1

Try this…

echo"<th>ImagePath:</th> <td><img src='".$row['imgPath'] . "' width='200' height='200' /> </td></tr>";

However see what you get for echo $row['imgPath']. I think the path is incorrect and hence you don’t see image.

Can you tell me what you get for echo $row['imgPath']