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Home/ Questions/Q 7932643
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Editorial Team
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Editorial Team
Asked: June 3, 20262026-06-03T21:04:41+00:00 2026-06-03T21:04:41+00:00

I have the following code which splits a string of numbers (separated by a

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I have the following code which splits a string of numbers (separated by a space) and then creates an array of floats :

//Split the string and then build a float array with the values.
String[] tabOfFloatString = value.split(" ");
int length = tabOfFloatString.length;
System.out.println("Length of float string is" + length);
float[] floatsArray = new float[length];
for (int l=0; l<length; l++) {
float res = Float.parseFloat(tabOfFloatString[l]);
    System.out.println("Float is " + res);
    floatsArray[l]=res;
}

The problem is that some of the values in the string are formatted with scientific notation – e.g they read -3.04567E-8.

What I want to do is end up with a float which does not contain the E number.

I have been reading this thread which suggests that I could use BigDecimal, however am unable to get this to work – is this the best approach or should I try something else ? How to convert a string 3.0103E-7 to 0.00000030103 in Java?

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  1. Editorial Team
    Editorial Team
    2026-06-03T21:04:43+00:00Added an answer on June 3, 2026 at 9:04 pm

    Below is your code slightly modified. As per me this works well and doesn’t actually cares he order of the exponents:

    public void function() {
        String value = "123456.0023 -3.04567E-8 -3.01967E-20";
        String[] tabOfFloatString = value.split(" ");
        int length = tabOfFloatString.length;
        System.out.println("Length of float string is" + length);
        float[] floatsArray = new float[length];
        for (int l = 0; l < length; l++) {
            String res = new BigDecimal(tabOfFloatString[l]).toPlainString();
            System.out.println("Float is " + res);
            floatsArray[l] = Float.parseFloat(res);
        }
    
    }
    
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