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Home/ Questions/Q 208145
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Editorial Team
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Editorial Team
Asked: May 11, 20262026-05-11T17:47:56+00:00 2026-05-11T17:47:56+00:00

I have the following code, which will retrieve a filename from a table and

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I have the following code, which will retrieve a filename from a table and make a link to it. What I want to do, is have it so I can refer to $filesList later on, and it will contain a single block of html code with links to as many files as there are files.

I thought adding to the previous variable would be the easiest way to do this, but it actually outputs nonsense code: 0test.sh">test.sh

if ($getFiles = $con->prepare($filesQuery)) {
    $getFiles->bind_param("s", $pk);
    $getFiles->execute();
    $getFiles->bind_result($FILENAME);
    $files = array();

    while ($getFiles->fetch()) {
         $filename = array(
         'FILENAME' => $FILENAME,
          );
           $files[] = $filename;
        }
}
$filesList = '';
foreach ($files as $filenames)
    {

    $filesList = $filesList + '<p><a href="./files/'. $filenames['FILENAME'] .'">'. $filenames['FILENAME'] .'</a>' . "\n"; 
  };

Sureley I do not need to have an array for what i want to do?

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-11T17:47:56+00:00Added an answer on May 11, 2026 at 5:47 pm

    You need to change that code to:

    $filesList = '';
    foreach ($files as $filenames)
    {
        $filesList .= '<p><a href="./files/'. $filenames['FILENAME'] .'">'. $filenames['FILENAME'] ."</a></p>\n"; 
    };
    

    Does that help? You cannot concatenate with +.

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