Sign Up

Sign Up to our social questions and Answers Engine to ask questions, answer people’s questions, and connect with other people.

Have an account? Sign In

Have an account? Sign In Now

Sign In

Login to our social questions & Answers Engine to ask questions answer people’s questions & connect with other people.

Sign Up Here

Forgot Password?

Don't have account, Sign Up Here

Forgot Password

Lost your password? Please enter your email address. You will receive a link and will create a new password via email.

Have an account? Sign In Now

You must login to ask a question.

Forgot Password?

Need An Account, Sign Up Here

Please briefly explain why you feel this question should be reported.

Please briefly explain why you feel this answer should be reported.

Please briefly explain why you feel this user should be reported.

Sign InSign Up

The Archive Base

The Archive Base Logo The Archive Base Logo

The Archive Base Navigation

  • Home
  • SEARCH
  • About Us
  • Blog
  • Contact Us
Search
Ask A Question

Mobile menu

Close
Ask a Question
  • Home
  • Add group
  • Groups page
  • Feed
  • User Profile
  • Communities
  • Questions
    • New Questions
    • Trending Questions
    • Must read Questions
    • Hot Questions
  • Polls
  • Tags
  • Badges
  • Buy Points
  • Users
  • Help
  • Buy Theme
  • SEARCH
Home/ Questions/Q 4620352
In Process

The Archive Base Latest Questions

Editorial Team
  • 0
Editorial Team
Asked: May 22, 20262026-05-22T02:32:56+00:00 2026-05-22T02:32:56+00:00

I have the following code which works fine and returns the expected results: DECLARE

  • 0

I have the following code which works fine and returns the expected results:

DECLARE @xmlList xml
SET @xmlList = '<Tx><T>1</T><T>2</T><T>3</T></Tx>'

SELECT
        X.Y.value('.', 'varchar(10)') AS [ID], 'OK' AS [Status]
    FROM @xmlList.nodes('/Tx/T') X(Y)

However, it also accept when I provide it with the following structure and returns the ssame results:

SET @xmlList = '<Tx><T>1</T></Tx><Tx><T>2</T><T>3</T></Tx>'

Notice how I don’t have a root element.

My question is, what do I need to change to make the code accept the first structure as valid and reject the other?

Thanks,

TheBlueSky

  • 1 1 Answer
  • 0 Views
  • 0 Followers
  • 0
Share
  • Facebook
  • Report

Leave an answer
Cancel reply

You must login to add an answer.

Forgot Password?

Need An Account, Sign Up Here

1 Answer

  • Voted
  • Oldest
  • Recent
  • Random
  1. Editorial Team
    Editorial Team
    2026-05-22T02:32:57+00:00Added an answer on May 22, 2026 at 2:32 am

    If you are only want to query one Tx node (the first) you can do like this

    SELECT
      X.Y.value('.', 'varchar(10)') AS [ID], 'OK' AS [Status]
    FROM @xmlList.nodes('/Tx[1]/T') X(Y)
    

    You could also check the number of root nodes and call raiserror if you have more than one root.

    select @xmlList.query('count(/Tx)').value('.', 'int')
    

    The technique used before the xml datatype only accepted one root node. sp_xml_preparedocument will raise and exception if there are more than one root.

    declare @idoc int
    exec sp_xml_preparedocument @idoc out, @xmlList
    exec sp_xml_removedocument @idoc
    
    • 0
    • Reply
    • Share
      Share
      • Share on Facebook
      • Share on Twitter
      • Share on LinkedIn
      • Share on WhatsApp
      • Report

Sidebar

Related Questions

I have the following code which works fine. However, I only want to return
I have the following code which works just fine when the method is POST,
I have code that looks like the following, which works fine for displaying the
I have the following code in my page which works fine although the number
I have the following code which returns results back from a database where columnName
I'm transforming xml using the following code. It works fine for one xslt but
I have the following code, which will not work. The javascript gives no errors
I'm trying to use opengl in C#. I have following code which fails with
I have following Code Block Which I tried to optimize in the Optimized section
Okay so I have the following Code which appends a string to another in

Explore

  • Home
  • Add group
  • Groups page
  • Communities
  • Questions
    • New Questions
    • Trending Questions
    • Must read Questions
    • Hot Questions
  • Polls
  • Tags
  • Badges
  • Users
  • Help
  • SEARCH

Footer

© 2021 The Archive Base. All Rights Reserved
With Love by The Archive Base

Insert/edit link

Enter the destination URL

Or link to existing content

    No search term specified. Showing recent items. Search or use up and down arrow keys to select an item.