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Home/ Questions/Q 6595753
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Editorial Team
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Editorial Team
Asked: May 25, 20262026-05-25T17:58:50+00:00 2026-05-25T17:58:50+00:00

I have the following code with urllib2 which prints HTTP Error 403: Forbidden but

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I have the following code with urllib2 which prints HTTP Error 403: Forbidden but if I use urllib instead to fetch url, I don’t see any error and I do get a list of my friends. The access token used is same in both the cases.

url = 'https://graph.facebook.com/me/friends/'
params = {'access_token': 'a valid access-token...', 'fields': 'id,name,birthday'}
req = urllib2.Request(url, data=urllib.urlencode(params))
try:
  con = urllib2.urlopen( req )
  print con.read()
except Exception as excp:
  print excp.read()

Please suggest what might be wrong.

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  1. Editorial Team
    Editorial Team
    2026-05-25T17:58:51+00:00Added an answer on May 25, 2026 at 5:58 pm

    This one is solved now. The trouble was that the request should be GET not POST and thus all the query parameters should be passed with url instead of being passed as POST data. So in my case the to get friends the code would look something like this:

    url = 'https://graph.facebook.com/me/friends/'
    params = {'access_token': 'a valid access-token...', 'fields': 'id,name,birthday'}
    
    try:
      con = urllib2.urlopen( url + '?' + urllib.urlencode(params))
      print con.read()
    except Exception as excp:
      print excp
    

    Hope it helps someone.

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