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Home/ Questions/Q 922605
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Editorial Team
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Editorial Team
Asked: May 15, 20262026-05-15T19:03:35+00:00 2026-05-15T19:03:35+00:00

I have the following (cut-down) class definition, and it has compilation errors. #include <iostream>

  • 0

I have the following (cut-down) class definition, and it has compilation errors.

#include <iostream>
#include <string>
class number
{
    public:
        friend std::ostream &operator << (std::ostream &s, const number &num);
        friend std::string  &operator << (std::string,     const number &num);
        friend std::istream &operator >> (std::istream &s,       number &num);
        friend std::string  &operator >> (std::string,           number &num);
    protected:
    private:
        void write (      std::ostream &output_target = std::cout) const;
        void read  (      std::istream &input_source  = std::cin);
        void to_string (      std::string &number_text) const;
        void to_number (const std::string &number_text);
};

std::istream & operator >> (std::istream &s,       number &num)
{
    num.read (s);
    return s;
}
std::string  & operator >> (std::string &s, number &num)
{
    num.to_number (s);
    return s;
}
std::string  & operator << (std::string &s, const number &num)
{
    num.to_string (s);
    return s;
}
std::ostream & operator << (std::ostream &s, const number &num)
{
    num.write (s);
    return s;
}

When I compile it, I get the following errors…

frag.cpp: In function ‘std::string& operator>>(std::string&, number&)’:
frag.cpp:17: error: ‘void number::to_number(const std::string&)’ is private
frag.cpp:27: error: within this context
frag.cpp: In function ‘std::string& operator<<(std::string&, const number&)’:
frag.cpp:16: error: ‘void number::to_string(std::string&) const’ is private
frag.cpp:32: error: within this context

Could anyone help with this; in particular why to_number and to_string are thought private but read and write are OK?

Thank you.

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-15T19:03:36+00:00Added an answer on May 15, 2026 at 7:03 pm

    The function signatures are different:

        friend std::string  &operator << (std::string,     const number &num);
        friend std::string  &operator >> (std::string,           number &num);
    

    are declared with a string parameter by value, while

    std::string  & operator >> (std::string &s, number &num) ...
    std::string  & operator << (std::string &s, const number &num) ...
    

    both have a string& reference parameter. So the function you actually implement is not the same as the one declared as friend – hence the error.

    Try changing the friend declaration to

        friend std::string  &operator << (std::string&,     const number &num);
        friend std::string  &operator >> (std::string&,           number &num);
    
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