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Home/ Questions/Q 4031244
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Editorial Team
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Editorial Team
Asked: May 20, 20262026-05-20T11:34:23+00:00 2026-05-20T11:34:23+00:00

I have the following data: Date ID Type Cost May 01 a A 1

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I have the following data:

 Date   ID Type Cost
 May 01   a  A    1
 May 01   b  A    2
 May 01   c  B    3
 May 01   d  B    4
 May 02   e  A    5
 May 02   f  A    6
 May 02   g  B    7
 May 02   h  B    8

I want a query that shows

Date       Type CostPercentage
May 01    A    (1+2) / (1+2+3+4)
May 01    B    (3+4) / (1+2+3+4)
May 02    A    (5+6) / (5+6+7+8)
May 02    B    (7+8) / (5+6+7+8)

What I currently have is

select Date, Type, sum(cost)
from mytable
group by Date, Type

I would really want to show the percentage, but that will involve deviding another number which is itself an aggregation.

How am I suppose to do that?

EDITED to reflect my real problem. I over simplified it before.

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  1. Editorial Team
    Editorial Team
    2026-05-20T11:34:24+00:00Added an answer on May 20, 2026 at 11:34 am

    You could use a subquery:

    select  dt.Date
    ,       dt.Type
    ,       SUM(dt.Cost) as DayTypeTotal
    ,       (select SUM(Cost) from @t d where d.Date = dt.Date) as DayTotal
    ,       100.0 * SUM(dt.Cost) / 
                 (select SUM(Cost) from @t d where d.Date = dt.Date) as Percentage
    from    @t dt
    group by
            dt.Date
    ,       dt.Type
    

    Link to working example @odata.

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