Question

I have the following dataframe (df)

 start     end
1    14379   32094
2   151884  174367
3   438422  449382
4   618123  621256
5   698271  714321
6   973394  975857
7   980508  982372
8   994539  994661
9  1055151 1058824
.   .       .
.   .       .
.   .       .

And a long boolean vector with boolean values (vec).

I would like to filter out all ranges in df that contain at least one TRUE value in the corresponding locations in vec.

In other words, a row with start=x end=y will be outputted iff !any(vec[x:y]).

Any ideas on how to accomplish that?

Answer 1

This is the same question as:
Adding a column to a dataframe in R
so it has the same answer… use apply, but with any instead of mean…

> ranges <- apply(DF,1,function(row) !any(vec[ row[1]:row[2] ]))
> DF[ranges,]