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Home/ Questions/Q 8428147
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Editorial Team
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Editorial Team
Asked: June 10, 20262026-06-10T04:58:25+00:00 2026-06-10T04:58:25+00:00

I have the following decorator with parameters: from functools import wraps def pdecor(p): def

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I have the following decorator with parameters:

from functools import wraps
def pdecor(p):
    def decorator(fn):
        @wraps(fn)
        def wrapper(*args, **kwargs):
            p -= 1
            return fn(*args, **wargs)
        return wrapper
    return decorator

Trying to use the decorator results in :

>>> @pdecor(1)
... def run(): pass
...
>>> run()
Traceback (most recent call last):
  File "<stdin>", line 1, in <module>
  File "<stdin>", line 5, in wrapper
UnboundLocalError: local variable 'p' referenced before assignment
>>>

Why can’t I change the p?

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-10T04:58:27+00:00Added an answer on June 10, 2026 at 4:58 am

    Because you assign to p inside wrapper, Python treats the p inside wrapper as local to wrapper. In Python 3 you can use nonlocal p to mark p as referenced from an outer scope. In Python 2 there is no way to assign to the intermediate p, although you can get a reference to the same value by passing it into the nested functions as a keyword argument (e.g., def decorator(fn, p=p)).

    However, it’s not clear what you’re getting at with this anyway. p is already only local to pdecor. No code outside pdecor can access p, so decrementing it won’t have any effect on any code elsewhere. So whether you can decrement p or not, it won’t really accomplish anything.

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