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Home/ Questions/Q 4577378
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Editorial Team
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Editorial Team
Asked: May 21, 20262026-05-21T20:20:16+00:00 2026-05-21T20:20:16+00:00

I have the following drop down list and selects the option based on the

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I have the following drop down list and selects the option based on the url e.g. http://www.domain.com/?car=Algema&city=Paris

The problem is thatI have 104 different forms and some of them are containg more than one dropdownlist. It is impossible to replace them. Is there a way to replace the $_GET['car'] with the $_GET['get the name of select id or name automatically'] ?

Maybe a re-writing regex script that will replace all my php files?

<select name="car" id="car" class="select">
<option value="Algema" <?php echo $_REQUEST['car'] == 'Algema' ? 'selected="selected"' : '';?>>Algema</option>
<option value="Barkas" <?php echo $_REQUEST['car'] == 'Barkas' ? 'selected="selected"' : '';?>>Barkas</option>
<option value="Cadillac" <?php echo $_REQUEST['car'] == 'Cadillac' ? 'selected="selected"' : '';?>>Cadillac</option>
</select>
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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-21T20:20:17+00:00Added an answer on May 21, 2026 at 8:20 pm

    Use something less repetitive like this:

    function makeSelect($name, $options) {
        foreach ($options as &$option) {
            $selected = isset($_GET[$name]) && $_GET[$name] == $option;
            $option = sprintf('<option value="%1$s"%2$s>%1$s</option>',
                              htmlspecialchars($option),
                              $selected ? ' selected="selected"' : null);
        }
    
        return sprintf('<select name="%1$s" id="%1$s" class="select">%2$s</select>',
                       htmlspecialchars($name),
                       join($options));
    }
    
    $options = array('Algema', 'Barkas', 'Cadillac', …);
    echo makeSelect('car', $options);
    

    You can probably automate the extraction of the option names into the array format using a Regex, but you’ll still have to confirm everything by hand at least.

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