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Home/ Questions/Q 5957465
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Editorial Team
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Editorial Team
Asked: May 22, 20262026-05-22T18:24:15+00:00 2026-05-22T18:24:15+00:00

I have the following function: convertToStr :: [Int] -> String convertToStr [] = []

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I have the following function:

convertToStr :: [Int] -> String
convertToStr [] = []
convertToStr (int:ints)
    | length (int:ints) == 1 = ((show (head (drop 0 (int:ints)))) ++ ", ")
    | length (int:ints) == 2 = ((show (head (drop 0 (int:ints)))) ++ ", ") ++ ((show (head (drop 1 (int:ints)))) ++ ", ")

As can be seen above, I have managed to get the following output from this input:

> convertToStr [3,5]
"3, 5, "

I seem, however to be stuck with regard to being able to write a recursive definition. I’d like to convert a list of any length in [Int] elements to a string with that list and not have it limited as such.

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  1. Editorial Team
    Editorial Team
    2026-05-22T18:24:16+00:00Added an answer on May 22, 2026 at 6:24 pm

    Without explicit recursion you can do it using map and intersperse like this

    convertToString :: [Int] -> String
    convertToString = concat . (intersperse ", ") . map show
    

    Edit: And with manual recursion it’s like

    cts [] = ""
    cts (x:xs)
       | null xs = show x 
       | otherwise = show x ++ ", " ++ cts xs
    
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