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Home/ Questions/Q 7916357
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Editorial Team
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Editorial Team
Asked: June 3, 20262026-06-03T14:46:36+00:00 2026-06-03T14:46:36+00:00

I have the following function EDIT: Changed int to class Long protected <T> ApiResponse<T>

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I have the following function

EDIT: Changed int to class Long

protected <T> ApiResponse<T> getApiResponse(Object obj, Class<T> clasx) 

How can I pass List<Long> class as the second argument?

Can I pass List<Long>.class but that is not working?

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  1. Editorial Team
    Editorial Team
    2026-06-03T14:46:37+00:00Added an answer on June 3, 2026 at 2:46 pm

    Type erasure means that you can only pass List.class.

    From the linked documentation:

    When a generic type is instantiated, the compiler translates those types by a technique called type erasure — a process where the compiler removes all information related to type parameters and type arguments within a class or method. Type erasure enables Java applications that use generics to maintain binary compatibility with Java libraries and applications that were created before generics.

    For instance, Box<String> is translated to type Box, which is called the raw type — a raw type is a generic class or interface name without any type arguments. This means that you can’t find out what type of Object a generic class is using at runtime. The following operations are not possible:

    public class MyClass<E> {
      public static void myMethod(Object item) {
        // Compiler error
        if (item instanceof E) {
            ...
        }
        E item2 = new E();       // Compiler error
        E[] iArray = new E[10];  // Compiler error
        E obj = (E)new Object(); // Unchecked cast warning
      }
    }
    

    The operations shown in bold are meaningless at runtime because the compiler removes all information about the actual type argument (represented by the type parameter E) at compile time.

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