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Home/ Questions/Q 6339115
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Editorial Team
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Editorial Team
Asked: May 24, 20262026-05-24T19:35:05+00:00 2026-05-24T19:35:05+00:00

I have the following function in C++ : char** f() { char (*v)[10] =

  • 0

I have the following function in C++ :

char** f()
{
    char (*v)[10] = new char[5][10];
    return v;
}

Visual studio 2008 says the following:

error C2440: 'return' : cannot convert from 'char (*)[10]' to 'char **'

What exactly should the return type to be, in order for this function to work?

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-24T19:35:07+00:00Added an answer on May 24, 2026 at 7:35 pm

    char** is not the same type as char (*)[10]. Both of these are incompatible types and so char (*)[10] cannot be implicitly converted to char**. Hence the compilation error.

    The return type of the function looks very ugly. You have to write it as:

    char (*f())[10]
    {
        char (*v)[10] = new char[5][10];
        return v;
    }
    

    Now it compiles.

    Or you can use typedef as:

    typedef char carr[10];
    
    carr* f()
    {
        char (*v)[10] = new char[5][10];
        return v;
    }
    

    Ideone.


    Basically, char (*v)[10] defines a pointer to a char array of size 10. It’s the same as the following:

     typedef char carr[10]; //carr is a char array of size 10
    
     carr *v; //v is a pointer to array of size 10
    

    So your code becomes equivalent to this:

    carr* f()
    {
        carr *v = new carr[5];
        return v;
    }
    

    cdecl.org helps here:

    • char v[10] reads as declare v as array 10 of char
    • char (*v)[10] reads as declare v as pointer to array 10 of char
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