Question

I have the following function:

inline auto iterateSomething(obj & o)
{
    auto iterators = baseIterator(o);
    auto tranformer = boost::bind(transofrmToSomething, _1, o);
    typedef boost::transform_iterator<decltype(tranformer), decltype(iterators.first)> iterator_t;
    iterator_t begin(iterators.first, tranformer);
    iterator_t end(iterators.second, tranformer);
    return std::make_pair(begin, end);
}

As you can see I don’t know the return value and even if I put int there and later copy the type from the error message, its a really long type…
Is there a way to specify the return type as the type of the only return in the function? is there any workaround not involving a huge type in the return type?

Answer 1

I think you should do what Raymond Chen suggested in a comment:

Move the typedefs outside the function. Then you can use it to declare the return type.

If Raymond posts an answer it should be accepted in preference to mine–I’m posting this so that bitmask’s answer is not the only one, since I think it is a cure worse than the disease.