Question

I have the following function

int namecomp(char c);

Part of the function code

else if (c == 'b' || 'B')
    i=2;

The way I am calling it in main()

j= namecomp(s);

and s is defined as char s = 'B';

There is an error and whenever I am trying to use j the value is always 1 in the main. Please help me to know where exactly the error is. Thanks!

EDIT:Sorry Folks none of it worked., I am posting the complete code for help

int main (int argc, char* argv [])
{
int i;                  
int j;
char s = 'B';
j= namecomp(s);
printf ("%d",j);
}

int namecomp(char c)
{
int i;

    if (c == 'a'||'A') 
        i=1;

    else if ((c == 'b' || c == 'B'))
    i=2;

    return i;

}

Answer 1

c == 'b' || 'B'

always evaluates to 1, because it’s parsed as

(c == 'b') || 'B'

I’m betting you want

(c == 'b') || (c == 'B')