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Editorial Team
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Asked: 2026-05-25T06:11:22+00:00

I have the following: $(function() { // Make images draggable. $(.item).draggable({ // Find position

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I have the following:

    $(function() {
    // Make images draggable.
    $(".item").draggable({

    // Find position where image is dropped.
    stop: function(event, ui) {

        // Show dropped position.
        var Stoppos = $(this).position();
        $("div#stop").text("STOP: \nLeft: "+ Stoppos.left + "\nTop: " + Stoppos.top);
    }

    });
});

This will get the position of the item when I drop it, but it is relative to the browser window, not the div they are within. How can I get their relative position?

edit-> Here is the html/css:

<style type="text/css">

.container {
    margin-top: 50px;
    cursor:move;
}
#screen {
    overflow:hidden;
    width:500px;
    height:500px;
    clear:both;
    border:1px solid black;
}                              

</style>

<body>

<div class="container">

    <div id="screen">
      <img id="productid_1" src="images/KeypadLinc OFF.jpg" class="item" alt="" title="" />
      <img id="productid_2" src="images/KeypadLinc ON.jpg" class="item" alt="" title="" />
    </div>

</div>


<div id="stop">Waiting image getting dropped...</div>
</body>
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1 Answer

  1. Editorial Team

    Give the parent div position: relative.

    #screen {
    position: relative;
    ...
}
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