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Asked: 2026-06-07T05:26:46+00:00

I have the following function: testit() { [ $1 == OK ] && echo

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I have the following function:

testit()
{
[ "$1" == "OK" ] && echo "good" || echo "bad"
}

but it doesn’t work as expected. I can call it with:

testit 'OK' #good
testit 'abc' #bad

but when I call it with:

testit '('

it fails with: “sh: closing paren expected”. I’ve quoted the string to test, so why it acts like there are no quotes?

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1 Answer

  1. Editorial Team

    This is most likely a bug in your shell implementation. I have tested your code on the latest CentOS and it works fine.

    testit '('
bad

 sh -version
GNU bash, version 4.1.2(1)-release (x86_64-redhat-linux-gnu)
Copyright (C) 2009 Free Software Foundation, Inc.
License GPLv3+: GNU GPL version 3 or later <http://gnu.org/licenses/gpl.html>

This is free software; you are free to change and redistribute it.
There is NO WARRANTY, to the extent permitted by law.
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