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Home/ Questions/Q 5939851
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Editorial Team
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Editorial Team
Asked: May 22, 20262026-05-22T15:53:11+00:00 2026-05-22T15:53:11+00:00

I have the following html button <td><form id=form2 name=form2 method=post onclick=../cgi-bin/py/GuestBookEntry.py> <input type=submit name=gBookSrib

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I have the following html button

<td><form id="form2" name="form2" method="post" onclick="../cgi-bin/py/GuestBookEntry.py">
<input type="submit" name="gBookSrib" id="gBookSrib" value="Sribble" />
</form></td>

My python script is

#!/usr/bin/python
print "Content-type: text/html\n\n"
print "<html><body>Hello World!</body></html>

When i click the button i want my serverside script to execute and create a html page. How do i do that?

My webhost service provider is fatcow. I think he runs apache, is there a way to check it though? Yes he supports python cgi script. He mentioned that if i place my ‘py’ files inside the cgi-bin, it should work, even without the ‘she’bang.

Fatcow does not allow custom modules. Only standard python modules. They had not allowed access to my cgi-bin folder by default, so had to call them, and then the below stuff just worked.

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  1. Editorial Team
    Editorial Team
    2026-05-22T15:53:12+00:00Added an answer on May 22, 2026 at 3:53 pm

    Which web server are you using?
    For apache2 there is very tidy module called apache2-modpython, that takes care of executing server-side python scripts and returning the result to the client.

    Using this module your python would look like:

    def index (req): return "<html><body>Hello World!</body></html>"
    

    Let’s say this script is called test.py and has the URI http://yourserver.tld/test.py, then your form would look like:

    <form id="form2" name="form2" method="post" action="test.py">
    

    Inside the entry of your site definition add the following lines

        AddHandler mod_python .py
        PythonHandler mod_python.publisher
        PythonDebug On
    
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