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Home/ Questions/Q 825183
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Editorial Team
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Editorial Team
Asked: May 15, 20262026-05-15T03:12:52+00:00 2026-05-15T03:12:52+00:00

I have the following HTML Code. What I’m try to do is to have

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I have the following HTML Code. What I’m try to do is to have the div named javaRatingDiv to be displayed once the checkbox with the name java is checked.

I can’t seem to figure out how to navigate to the next TD in a table via jquery.

<div id="languages">
   <table style="width:inherit">
   <tr style="height:50px; vertical-align:top">
     <td>Select the languages that you are familiar with and rate your knowledge:</td>
   </tr>
   <tr>
     <table style="width:75%;" align="center">   
     <tr id="tableRow"> 
       <td id="firstTD"><input type="checkbox" name="java" value="java" />&nbsp;Java</td>
       <td id="secondTD" style="width:200px;">
         <div id="javaRatingDiv" style="display:none">
           <input name="javaRating" type="radio" value="1" class="star"/>
           <input name="javaRating" type="radio" value="2" class="star"/>
         </div>
       </td>
     </tr>
     </table>
    </tr>
    </table>
</div>
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  1. Editorial Team
    Editorial Team
    2026-05-15T03:12:53+00:00Added an answer on May 15, 2026 at 3:12 am

    For the sake of the question and the case of multiple “javaRatingDivs” this would work inside the checkbox click function:

    $(this).parent().next().find('div').show();
    

    .parent() gets the parent element
    .next() gets the next sibling, such as the NEXT td
    .find(selector) lets you find something within that sibling

    This info is for when you get into the issues of multiple items and NOT having ID’s to reference directly. In your above case, $(‘#javaRatingDiv’).show(); would work great as patrick mentioned.

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