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Editorial Team
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Asked: 2026-05-26T06:17:16+00:00

I have the following image list on an html page that I am converting

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I have the following image list on an html page that I am converting into php to be driven from a mysql database. While I thought it was a simple enough procedure -I am struggling to avoid syntax errors because of the existing use of ‘ in my code.

I need to convert a simple list of images into an array based on what is in the database. The html list is:

<li><a  href='javascript:void(0);' rel="{gallery: 'gal1', smallimage: './imgProd/2.jpg',largeimage: './imgProd/2.jpg'}">
<img src='imgProd/2.jpg' style="width:110px; height:110px;"></a></li>

<li><a  href='javascript:void(0);' rel="{gallery: 'gal1', smallimage: './imgProd/3.jpg',largeimage: './imgProd/3.jpg'}">
<img src='imgProd/3.jpg' style="width:110px; height:110px;"></a></li>

<li><a  href='javascript:void(0);' rel="{gallery: 'gal1', smallimage: './imgProd/4.jpg',largeimage: './imgProd/4.jpg'}">
<img src='imgProd/4.jpg' style="width:110px; height:110px;"></a></li>

I am trying to generate this from php using:

 <?php

$result = mysql_query("SELECT * FROM table WHERE id='$id'");
while($row = mysql_fetch_array($result))
{
    echo '<li>';
    echo '<a href='javascript:void(0);' rel="{gallery: 'gal1', smallimage: './' . $row['photo'] . '',largeimage: './' . $row['photo'] . ''}">';
    echo '<img src=' . $row['photo'] . '' style="width:110px; height:110px;">';
    echo '</a>';
    echo '</li>';
}
?>

but am obviously getting loads of syntax errors as I am attempting to use single quotes within single quotes (I assume!?). Does anyone know how I can incoporate this list into an array??

Thanks very much in advance

JD

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1 Answer

  1. Editorial Team

    Escaping the quotes is a bad idea.

    You can either simply close and reopen your <?php ?> tags or use Heredoc syntax.

    Using tags (PHP is a templating language, anything that isn’t between <?php ?> tags will be send to the client exactly as it is):

    <?php    
$result = mysql_query("SELECT * FROM table WHERE id='$id'");
while($row = mysql_fetch_array($result))
{
?>
<li>
<a href='javascript:void(0);' rel="{gallery: 'gal1', smallimage: './<?php echo $row['photo']; ?>',largeimage: './<?php echo $row['photo']; ?>'}">
<img src='<?php echo $row['photo']; ?>' style="width:110px; height:110px;">
</a>
</li><?php
}
?>

    Using Heredoc (the closing HTML; should be on its on line, unindented):

    <?php    
$result = mysql_query("SELECT * FROM table WHERE id='$id'");
while($row = mysql_fetch_array($result))
{    
    echo <<<HTML
    <li>
    <a href='javascript:void(0);' rel="{gallery: 'gal1', smallimage: './{$row['photo']}',largeimage: './{$row['photo']}'}">
    <img src='{$row['photo']}' style="width:110px; height:110px;">
    </a>
    </li>
HTML;
}
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