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Home/ Questions/Q 4346638
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Editorial Team
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Editorial Team
Asked: May 21, 20262026-05-21T12:11:58+00:00 2026-05-21T12:11:58+00:00

I have the following implicit rule: CFLAGS=-I../tcp/ -I../libip_udp/ -g -Wall LDLIBS=framework.o ../tcp/libtcp.a ../libip_udp/libip.a %.run

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I have the following implicit rule:

CFLAGS=-I../tcp/ -I../libip_udp/ -g -Wall                                        
LDLIBS=framework.o ../tcp/libtcp.a ../libip_udp/libip.a                          

%.run : %.c $(LDLIBS)                                                            
        $(CC) $< $(LDLIBS) -o $@ $(CFLAGS)                                       
        ./$@

If I run make foo.run it will compile foo.c and execute foo.run. However, running make foo.run a second time will not do anything. How can I split the implicit rule such that it compiles when needed, but runs always?

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  1. Editorial Team
    Editorial Team
    2026-05-21T12:11:59+00:00Added an answer on May 21, 2026 at 12:11 pm

    For example:

    CFLAGS=-I../tcp/ -I../libip_udp/ -g -Wall
    LDLIBS=framework.o ../tcp/libtcp.a ../libip_udp/libip.a
    
    .SECONDARY:
    
    %.run : %.c $(LDLIBS)
            $(CC) $< $(LDLIBS) -o $@ $(CFLAGS)
    
    exec.%: %
            ./$<
    

    Now just run it

    make exec.foo.run
    
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