Sign Up

Sign Up to our social questions and Answers Engine to ask questions, answer people’s questions, and connect with other people.

Have an account? Sign In

Have an account? Sign In Now

Sign In

Login to our social questions & Answers Engine to ask questions answer people’s questions & connect with other people.

Sign Up Here

Forgot Password?

Don't have account, Sign Up Here

Forgot Password

Lost your password? Please enter your email address. You will receive a link and will create a new password via email.

Have an account? Sign In Now

You must login to ask a question.

Forgot Password?

Need An Account, Sign Up Here

Please briefly explain why you feel this question should be reported.

Please briefly explain why you feel this answer should be reported.

Please briefly explain why you feel this user should be reported.

Sign InSign Up

The Archive Base

The Archive Base Logo The Archive Base Logo

The Archive Base Navigation

  • SEARCH
  • Home
  • About Us
  • Blog
  • Contact Us
Search
Ask A Question

Mobile menu

Close
Ask a Question
  • Home
  • Add group
  • Groups page
  • Feed
  • User Profile
  • Communities
  • Questions
    • New Questions
    • Trending Questions
    • Must read Questions
    • Hot Questions
  • Polls
  • Tags
  • Badges
  • Buy Points
  • Users
  • Help
  • Buy Theme
  • SEARCH
Home/ Questions/Q 6358609
In Process

The Archive Base Latest Questions

Editorial Team
  • 0
Editorial Team
Asked: May 24, 20262026-05-24T23:24:36+00:00 2026-05-24T23:24:36+00:00

I have the following in myfile.php $json_data = ‘{type:email,msg:some text}’; Instead of typing email

  • 0

I have the following in myfile.php

$json_data = '{"type":"email","msg":"some text"}';

Instead of typing “email” or “some text” I want to concat the php variables $thetype and $themsg to the line before.

How can I do that? No matter what I do I get a syntax error.

I’m trying:

$json_data = '{"type":"+$thetype+","msg":"+$themsg+"}';

But as I say errors galore.

Thanks a lot

  • 1 1 Answer
  • 0 Views
  • 0 Followers
  • 0
Share
  • Facebook
  • Report

Leave an answer
Cancel reply

You must login to add an answer.

Forgot Password?

Need An Account, Sign Up Here

1 Answer

  • Voted
  • Oldest
  • Recent
  • Random
  1. Editorial Team
    Editorial Team
    2026-05-24T23:24:37+00:00Added an answer on May 24, 2026 at 11:24 pm

    Your question is a little vague…

    Are you looking for this?

    $json = array('type' => $thetype, 'msg' => $themsg);
    $json_data = json_encode($json);
    

    That will set $json_data to a string like what you described:

    <?php
    
    $thetype = 'something';
    $themsg = 'something else';
    $json = array('type' => $thetype, 'msg' => $themsg);
    $json_data = json_encode($json);
    var_dump($json_data);
    

    Would print:

    string(43) "{"type":"something","msg":"something else"}"
    

    See the PHP manual for json_encode.

    You could try and build the string by hand, like this:

    $json_data = '{"type":"'. addcslashes($thetype,"\"'\n").'","msg":"'. addcslashes($themsg,"\"'\n").'"}';
    

    But, you’ll generally be better off using json_encode, as it’s designed for this purpose and is much less likely to produce invalid JSON.

    • 0
    • Reply
    • Share
      Share
      • Share on Facebook
      • Share on Twitter
      • Share on LinkedIn
      • Share on WhatsApp
      • Report

Sidebar

Related Questions

I have the following HTML: <a><img src=myfile.png /> Some text</a> And this css: a:hover
I have following string String str = replace :) :) with some other string;
I have following text in a file 23456789 When I tried to replace the
I have an HTML form POSTing to the following index.php: <?php require_once(/home/full/path/to/included/file.php); ?> And
I have the following pages: page1.php, page2.php and page3.php. Code in each of them
I have the following: XDocument xdoc = XDocument.Load(C:\\myfile.xml); List<Tag> list = new List<Tag>(); foreach
I have the following sorted data: AAA AAA TCG TTT TTT TTT I want
I have the following code (simplified) int main() { ifstream myFile(input.txt); if(myFile.is_open()) cout<<test; }
I am trying to import an SQL dump via PHP. I have the following
i have this following php code : $filename = '/front/style.css'; $cssfile='#h1{font-size:12px}'; if($id_file=fopen($filename, w+)) {

Explore

  • Home
  • Add group
  • Groups page
  • Communities
  • Questions
    • New Questions
    • Trending Questions
    • Must read Questions
    • Hot Questions
  • Polls
  • Tags
  • Badges
  • Users
  • Help
  • SEARCH

Footer

© 2021 The Archive Base. All Rights Reserved
With Love by The Archive Base

Insert/edit link

Enter the destination URL

Or link to existing content

    No search term specified. Showing recent items. Search or use up and down arrow keys to select an item.