Question

I have the following input XML:

<root age="1">
<description>some text</description>
<section>
    <item name="a">
        <uuid>1</uuid>
    <item>
</section>
<section>
    <item name="b">
        <uuid>2</uuid>
    <item>
</section>
</root>

I would like to transform it into the following XML:

<root age="1">
<description>some text</description>
<section>
    <item name="a">
        <uuid>1</uuid>
    <item>
    <item name="b">
        <uuid>2</uuid>
    <item>
</section>
</root>

Thanks in advance.

Answer 1

A simpler and shorter solution:

<xsl:stylesheet version="1.0"
 xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
 <xsl:output omit-xml-declaration="yes" indent="yes"/>
 <xsl:strip-space elements="*"/>

 <xsl:template match="node()|@*">
     <xsl:copy>
       <xsl:apply-templates select="node()|@*"/>
     </xsl:copy>
 </xsl:template>

 <xsl:template match="section[1]">
   <section>
     <xsl:apply-templates select="../section/node()"/>
   </section>
 </xsl:template>

 <xsl:template match="section[position() > 1]"/>
</xsl:stylesheet>

When this transformation is applied on the provided XML document:

<root age="1">
    <description>some text</description>
    <section>
        <item name="a">
            <uuid>1</uuid>
        </item>
    </section>
    <section>
        <item name="b">
            <uuid>2</uuid>
        </item>
    </section>
</root>

the wanted, correct result is produced:

<root age="1">
   <description>some text</description>
   <section>
      <item name="a">
         <uuid>1</uuid>
      </item>
      <item name="b">
         <uuid>2</uuid>
      </item>
   </section>
</root>