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I have the following jqGrid script:
jQuery("#editgrid").jqGrid({
url: "editing.php?q=1",
datatype: "xml",
// ...
Where should the url point to if I am using Java instead PHP for creating the crud?
It should just point to an URL where you’ve some Java code running and listening on the particular URL. In a Java webapplication you normally use a Servlet class for this. Just let the URL match the
<url-pattern>of the Servlet class as you’ve definied in theweb.xml. In the Servlet class you just implementdoGet()method accordingly to handle the HTTP GET request and response.