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Home/ Questions/Q 7447575
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Editorial Team
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Editorial Team
Asked: May 29, 20262026-05-29T12:39:16+00:00 2026-05-29T12:39:16+00:00

I have the following line of code: double *resultOfMultiplication = new double(*num1 * *num2);

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I have the following line of code:

double *resultOfMultiplication = new double(*num1 * *num2);

How does the compiler know which * is used for derefencing and which * is used for multiplication?

Also, and probably a more important question is in this case is double a primitive (like in Java) or an object? If it’s a primitive how can I create a new one?

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  1. Editorial Team
    Editorial Team
    2026-05-29T12:39:16+00:00Added an answer on May 29, 2026 at 12:39 pm

    Dereference comes first, so *num1 * *num2 gets parsed as (*num1) * (*num2), which is unambiguous. *resultOfMultiplication is not parsed as dereference because it is a variable definition. In such a context, the compiler expects a data type followed by an identifier so the asterisk is unambiguous.

    Primitive data types are still objects in C++. If you use new on a primitive type, all that happens is that enough memory in the free store to hold the object is allocated and its address returned to you. This is unlike ‘normal’ variables (i.e. double t;), which are of automatic or static storage duration.

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