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Home/ Questions/Q 1076377
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Editorial Team
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Editorial Team
Asked: May 16, 20262026-05-16T21:24:38+00:00 2026-05-16T21:24:38+00:00

I have the following logic to remove inactive users in the system, since we

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I have the following logic to remove inactive users in the system, since we cannot remove a row while iterating on the list. Is there a better way to handle this?

List<User> users = new ArrayList<User>();
List<User> removeUsers = new ArrayList<User>();

for (User user : users) {
  if (!user.isActive()) {
      removeUsers.add(user);
  }
}

users.removeAll(removeUsers);
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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-16T21:24:39+00:00Added an answer on May 16, 2026 at 9:24 pm

    That’s a perfectly fine way to do it IMHO.

    Other ways that I might do it, use indexing and remove as you loop through in reverse.

    for (int i = users.size()-1; i >= 0; i--)
    {
        if (!users.get(i).isActive())
        {
            users.remove(i);
        }
    }
    

    Or create a new list of the items to be kept and replace it with the old list.

    List<User> newUsers = new ArrayList<User>();
    for (User user : users)
    {
        if (user.isActive())
        {
            newUsers.add(user);
        }
    }
    users = newUsers;
    

    Can’t think of any others at the moment.

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