Question

I have the following loop that simply checks all “green” rows in a table called items to see which one contains a hidden input element called xxx that does not match a given value:

$('table#items tr.green').each(function () {
    if (myvalue != $('input#xxx', $(this)).val()){
        alert('The xxx element is not the same as ' + myvalue + ' on all green rows');
        return;
    }
});

But there is a jQuery.ajax() request below this code and even when the alert box is displayed, the jQuery.ajax() still runs! Any idea why?

Answer 1

what you want is to return the function outside of the each? you cant just return inside the each, each generates a function, you return now this funktion is closed, the loop still runs, you have to do something like this

var continue = true;

jQuery(bla).each(function(){
    if(bla == blubb){
        continue = false;
    }
});

if(!continue){
    return
}