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Home/ Questions/Q 8174889
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Editorial Team
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Editorial Team
Asked: June 6, 20262026-06-06T22:34:44+00:00 2026-06-06T22:34:44+00:00

I have the following macro: ‎#define GTR(type) \‎ type type##_gtr(type a, type b) \‎

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I have the following macro:

‎#define GTR(type) \‎
type type##_gtr(type a, type b) \‎
‎{ \‎
‎   return a > b ? a : b;\‎
‎}‎

I understand that it generates functions, but if GTR(unsigned int) expands outside main(), how do I call the generated function? _gtr(a, b) does not work…

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  1. Editorial Team
    Editorial Team
    2026-06-06T22:34:45+00:00Added an answer on June 6, 2026 at 10:34 pm

    GTR(unsigned) would expand to:

    unsigned unsigned_gtr(unsigned a, unsigned b)
    {
    ‎   return a > b ? a : b;
    }‎
    

    In that case, you should call unsigned_gtr(a, b).

    GTR(unsigned int), however, would fail with a syntax error because you are having two separate tokens and the name of the function cannot be properly produced.

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