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Home/ Questions/Q 7060865
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Editorial Team
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Editorial Team
Asked: May 28, 20262026-05-28T04:24:15+00:00 2026-05-28T04:24:15+00:00

I have the following markup: <!– first marker –> <div class=marker></div> <div class=tooltip> <p>My

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I have the following markup:

<!-- first marker -->
<div class="marker"></div>
<div class="tooltip">
    <p>My tooltip content"</p>
</div>

<!-- second marker -->
<div class="marker"></div>
<div class="tooltip">
    <p>My tooltip content"</p>
</div> 

<!-- repeating..... -->

and the following jQuery javascript:

$(document).ready(function() {

    $(".marker").hover(function(event){
        $('.tooltip').hide();
        $(this).next('.tooltip').slideDown('fast');
    });

});

How can I modify this script so that on hover all other open div.tooltips hide except for the next one? Currently it tries to hide all.

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-28T04:24:16+00:00Added an answer on May 28, 2026 at 4:24 am

    You can use the not function to omit a particular element

    $(".marker").hover(function(event){
        var nextEl = $(this).next("div.tooltips");
        $('.tooltip').not(nextEl).hide();
        $(this).next('.tooltip').slideDown('fast');
    });
    

    EDIT

    Also, you’ll likely want to also pass a second function to hover so that things clean up when the hover ends:

    $(".marker").hover(function(event){
        var nextEl = $(this).next("div.tooltips");
        $('.tooltip').not(nextEl).hide();
        $(this).next('.tooltip').slideDown('fast');
    }, function() {
        $('.tooltip').hide();
    });
    
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