Question

I have the following method in my code:

private bool GenerateZipFile(List<FileInfo> filesToArchive, DateTime archiveDate) {     try     {         using (ZipOutputStream zipStream = new ZipOutputStream(File.Create(GetZipFileName(archiveDate))))         {             zipStream.SetLevel(9); // maximum compression.             byte[] buffer = new byte[4096];              foreach (FileInfo fi in filesToArchive)             {                 string fileName = ZipEntry.CleanName(fi.Name);                 ZipEntry entry = new ZipEntry(fileName);                 entry.DateTime = fi.LastWriteTime;                 zipStream.PutNextEntry(entry);                  using (FileStream fs = File.OpenRead(fi.FullName))                 {                     StreamUtils.Copy(fs, zipStream, buffer);                 }                  zipStream.CloseEntry();             }              zipStream.Finish();             zipStream.Close();         }         return true;      }     catch (Exception ex)     {         OutputMessage(ex.ToString());         return false;     } } 

This code generates a ZIP file with all the correct entries, but each file is listed as being 4 TB (both unpacked and packed) and creates the following error when I try to open it:

Extracting to 'C:\winnt\profiles\jbladt\LOCALS~1\Temp\' Use Path: no   Overlay Files: yes skipping: QPS_Inbound-20081113.txt: this file is not in the standard Zip 2.0 format    Please see www.winzip.com/zip20.htm for more information error:  no files were found - nothing to do 

The code is practically taken from the samples, but I seem to be missing something. Does anyone have any pointers?

Answer 1

I used to use SharpZipLib until I switched to DotNetZip You may want to check it out as an alternative.

Example:

try    {      using (ZipFile zip = new ZipFile('MyZipFile.zip')      {        zip.AddFile('c:\\photos\\personal\\7440-N49th.png');        zip.AddFile('c:\\Desktop\\2005_Annual_Report.pdf');        zip.AddFile('ReadMe.txt');        zip.Save();      }    }    catch (System.Exception ex1)    {      System.Console.Error.WriteLine('exception: ' + ex1);    }