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Asked: May 11, 20262026-05-11T14:59:05+00:00 2026-05-11T14:59:05+00:00

I have the following model: public class Model : INotifyPropertyChanged { public ObservableCollection<ViewElement> Elements

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I have the following model:

public class Model : INotifyPropertyChanged  {   public ObservableCollection<ViewElement> Elements { get; set; }    public ViewElement CurrentElement { get; set; } } 

And the following grid where the parent DataContext is the above model:

<dg:XamDataGrid DataSource='{Binding Path=Elements}' /> 

I want to bind the CurrentElement property to the Selected Item of the Grid, similar to how I would in a ListView:

    <ListView x:Name='playbackSteps'           ItemsSource='{Binding Path=Elements}'           SelectedItem='{Binding Path=CurrentElement}' /> 

How would you suggest I do this?

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  1. 2026-05-11T14:59:06+00:00Added an answer on May 11, 2026 at 2:59 pm

    As stated on the Infragistics forum, the XamDataGrid exposes an IsSynchronizedWithCurrentItem property. To take advantage of this, you need a ListCollectionView of your ObservableCollection. Something like this:

    public ListCollectionView ElementsView {get;set;}  // In the constructor: this.ElementsView = new ListCollectionView(Elements); 

    Then bind your XamDataGrid to ElementsView.

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