Sign Up

Sign Up to our social questions and Answers Engine to ask questions, answer people’s questions, and connect with other people.

Have an account? Sign In

Have an account? Sign In Now

Sign In

Login to our social questions & Answers Engine to ask questions answer people’s questions & connect with other people.

Sign Up Here

Forgot Password?

Don't have account, Sign Up Here

Forgot Password

Lost your password? Please enter your email address. You will receive a link and will create a new password via email.

Have an account? Sign In Now

You must login to ask a question.

Forgot Password?

Need An Account, Sign Up Here

Please briefly explain why you feel this question should be reported.

Please briefly explain why you feel this answer should be reported.

Please briefly explain why you feel this user should be reported.

Sign InSign Up

The Archive Base

The Archive Base Logo The Archive Base Logo

The Archive Base Navigation

  • SEARCH
  • Home
  • About Us
  • Blog
  • Contact Us
Search
Ask A Question

Mobile menu

Close
Ask a Question
  • Home
  • Add group
  • Groups page
  • Feed
  • User Profile
  • Communities
  • Questions
    • New Questions
    • Trending Questions
    • Must read Questions
    • Hot Questions
  • Polls
  • Tags
  • Badges
  • Buy Points
  • Users
  • Help
  • Buy Theme
  • SEARCH
Home/ Questions/Q 6033299
In Process

The Archive Base Latest Questions

Editorial Team
  • 0
Editorial Team
Asked: May 23, 20262026-05-23T05:27:49+00:00 2026-05-23T05:27:49+00:00

I have the following MySQL line: SELECT age, count(*) AS total FROM pacient WHERE

  • 0

I have the following MySQL line:

SELECT age, count(*) AS total FROM pacient WHERE age BETWEEN 20 AND 40 GROUP BY age ORDER BY age and I need to add an additional column to it that shows ONLY the max value of the count(*) for every row. For example:

13 2 7
18 2 7
23 5 7
24 7 7
26 6 7
32 3 7
38 1 7
41 1 7
46 4 7

This would be 3 columns and the 3rd column shows 7 since 7 was the highest number in the second column where the count(*) is made.

  • 1 1 Answer
  • 0 Views
  • 0 Followers
  • 0
Share
  • Facebook
  • Report

Leave an answer
Cancel reply

You must login to add an answer.

Forgot Password?

Need An Account, Sign Up Here

1 Answer

  • Voted
  • Oldest
  • Recent
  • Random
  1. Editorial Team
    Editorial Team
    2026-05-23T05:27:50+00:00Added an answer on May 23, 2026 at 5:27 am

    Here the solution:

    select age,
        count(*),
        (select max(c) from 
            (select count(*) as c from pacient where age between 20 and 40 group by age) as x) as t 
    from pacient 
    where age between 20 and 40 
    group by age 
    order by age;
    
    • 0
    • Reply
    • Share
      Share
      • Share on Facebook
      • Share on Twitter
      • Share on LinkedIn
      • Share on WhatsApp
      • Report

Sidebar

Related Questions

I have the following mySQL code: SELECT c.categoryId, c.categoryName, c.categoryParent, c.categoryDescription, COUNT(p.productid) as totalProdsInCategory
I have the following query in MySQL SELECT *,(select lat from node where id=node_id)as
I have the following line of code : mysql_query(SELECT name FROM details WHERE md5(name)
I have the following MySQL-query: SELECT s.student_socialnr, s.student_lastname, s.student_firstname, cs.city_name, scp.cpl_startdate, scp.cpl_enddate, scp.cpl_invoice, cu.customer_name,
I have the following Mysql Table Order table status 0 - incomplete status 1
I have the following Java code: String query = Select 1 from myTable where
The following line is giving an error message. $query = 'SELECT * FROM products
I have the following query: SELECT * FROM ships WHERE shipCode=SP SELECT * FROM
I have 3 chain select boxes that return three values from the same line
The following query will not execute mysql_query(SELECT * FROM order WHERE orderID = 102;);

Explore

  • Home
  • Add group
  • Groups page
  • Communities
  • Questions
    • New Questions
    • Trending Questions
    • Must read Questions
    • Hot Questions
  • Polls
  • Tags
  • Badges
  • Users
  • Help
  • SEARCH

Footer

© 2021 The Archive Base. All Rights Reserved
With Love by The Archive Base

Insert/edit link

Enter the destination URL

Or link to existing content

    No search term specified. Showing recent items. Search or use up and down arrow keys to select an item.