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Home/ Questions/Q 929931
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Editorial Team
  • 0
Editorial Team
Asked: May 15, 20262026-05-15T20:15:08+00:00 2026-05-15T20:15:08+00:00

I have the following MySQL Query: <div class=box id=settlement1> <? $query = SELECT name,

  • 0

I have the following MySQL Query:

<div class="box" id="settlement1">
        <?
            $query  = "SELECT name, pub, hospital, trade FROM settlements WHERE settlementID = 1";
            $result = mysql_query($query);

            while($row = mysql_fetch_array($result, MYSQL_ASSOC)) {
                $settlementName = $row['name'];
                $pubExists = $row['pub'];
                $hospitalExists = $row['hospital'];
                $tradeExists = $row['trade'];
            }
        ?>
        <div class="settlement-name"><? echo $settlementName; ?></div>
        <div class="settlement-contents">
            <?
                if ($hospitalExists == '1') { echo "<div class='hospital'>HOSPITAL</div>";  }
                if ($pubExists == '1') { echo "<div class='pub'>PUB</div>"; }
                if ($tradeExists == '1') { echo "<div class='trade'>TRADE</div>"; }
            ?>
        </div>
    </div>
    <div class="box" id="settlement2">
        <?
            $query  = "SELECT name, shop, hospital, trade FROM settlements WHERE settlementID = 2";
            $result = mysql_query($query);

            while($row = mysql_fetch_array($result, MYSQL_ASSOC)) {
                $settlementName = $row['name'];
                $pubExists = $row['pub'];
                $hospitalExists = $row['hospital'];
                $tradeExists = $row['trade'];
            }
        ?>
        <div class="settlement-name"><? echo $settlementName; ?></div>
        <div class="settlement-contents">
            <?
                if ($hospitalExists == '1') { echo "<div class='hospital'>HOSPITAL</div>";  }
                if ($pubExists == '1') { echo "<div class='pub'>PUB</div>"; }
                if ($tradeExists == '1') { echo "<div class='trade'>TRADE</div>"; }
            ?>
        </div>
    </div>

Now, the first query works fine, but the second returns the same results as the first.

ALL FIELDS ARE DIFFERENT IN QUERY 1 TO QUERY 2

^_^ <( HELP! )

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-15T20:15:09+00:00Added an answer on May 15, 2026 at 8:15 pm

    I’m not sure if this is the cause but…

    first SQL:

    $query  = "SELECT name, pub, hospital, trade FROM settlements WHERE settlementID = 1";
    

    Second:

    $query  = "SELECT name, shop, hospital, trade FROM settlements WHERE settlementID = 2";
    

    in first one there’s pub, in second one – shop. But you don’t use shop value in PHP in second case, only pub (which is not in this SQL fields.

    You may have SQL error here (no field in database) or PHP error (checking non-existent field in result array).

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