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Home/ Questions/Q 8602125
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Editorial Team
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Editorial Team
Asked: June 12, 20262026-06-12T02:00:21+00:00 2026-06-12T02:00:21+00:00

I have the following MySql script: SET @skip = 0; SET @max = (SELECT

  • 0

I have the following MySql script:

SET @skip = 0;
SET @max = (SELECT COUNT(*) FROM table1);

CREATE TEMPORARY TABLE TempTable(
   id INT NOT NULL,
   name VARCHAR(32) NOT NULL
);

loop1: LOOP
  INSERT INTO TempTable (id, name) SELECT id, name FROM table1 LIMIT @skip, 1;

  IF @skip < @max THEN
    SET @skip = @skip + 1;
    ITERATE loop1;
  END IF;
  LEAVE loop1;
END LOOP loop1;

SELECT * FROM TempTable;

This script is not working but it should select all the id and names in table1. I am using a loop because I am also going to do other stuff in those loops but that is for later.
I am not looking for a solution like SELECT id, name FROM table1 but I want my error fixed. So I can continue with my loop.

The error I get is:

1064 – You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use
near ‘loop1: LOOP INSERT INTO TempTable (id, name) SELECT id, name
FROM table1’ at line 1

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  1. Editorial Team
    Editorial Team
    2026-06-12T02:00:22+00:00Added an answer on June 12, 2026 at 2:00 am

    There is a syntax error in your code (the LIMIT @skip which is dynamic SQL and requires some tricks to make it work) but it is not at loop1: LOOP.

    My guess is you are trying to use LOOP outside a compound statement (BEGIN … END) like a stored procedure, which is not possible. You have to create a stored procedure to do that.

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