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Home/ Questions/Q 225673
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Editorial Team
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Editorial Team
Asked: May 11, 20262026-05-11T19:26:11+00:00 2026-05-11T19:26:11+00:00

I have the following Perl script that generates a string based on a number:

  • 0

I have the following Perl script that generates a string based on a number:

my @chars;
push @chars, map(chr, 48..57), map(chr, 97..122);
my $c = $#chars+1;

for (0..50) {
    my $string;
    my $l = $_ / $c;
    my $i = int $l;
    my $r = ($l - $i) * $c;
    $string .= $chars[$r];
    while ($i > 0) {
        $l = $i / $c;
        $i = int $l;
        $r = ($l - $i) * $c;
        $string .= $chars[$r];
    }
    print "$string\n";
}

When I run this I get the following output:

0
1
2
3
4
...
z
01
01
21
21
41
41
61
61
81
91
91
b1
b1
d1
d1

What am I missing? Thankful for any help!

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-11T19:26:12+00:00Added an answer on May 11, 2026 at 7:26 pm

    Try this instead, it’s a little clearer than the script you have and properly converts to an arbitrary base:

    my @chars;
    push @chars, map(chr, 48..57), map(chr, 97..122);
    
    my $base = @chars;
    
    for my $num (0..100) {
        my $string = '';
    
        while ($num >= $base) {
            my $r = $num % $base;
            $string .= $chars[$r];
    
            $num = int($num / $base);
        }
        $string .= $chars[$num];
        print reverse($string) . "\n";
    }
    
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