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Home/ Questions/Q 6549261
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Editorial Team
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Editorial Team
Asked: May 25, 20262026-05-25T12:04:18+00:00 2026-05-25T12:04:18+00:00

I have the following PHP code: echo <form name=’CLChange’ method=’post’ action=”>; echo <td><select name=’NewClearanceLevel’>\n;

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I have the following PHP code:

echo "<form name='CLChange' method='post' action=''>";
echo "<td><select name='NewClearanceLevel'>\n";
for($i = 1; $i < $ClearanceLevel; $i++)
{
    echo "<option value='" . $i . "'>" . $i . "\n";
}
echo"<input type='submit' value='Change'></td></form>";

I want to be able to pass on an other value representing the current table row (This creates a table with which I should be able to make changes to an individual user). It has a row for every user. It looks roughly like this:

User          ID      Clearance Level    New Clearance Level

User 1        1       4                  (Drop down list and submit button)

User 2        2       3                  (Drop down list and submit button)

User 3        3       1                  (Drop down list and submit button)

Each drop down list and button is an individual form.

How can I do it so that I can pass an additional value as to know which user I am talking about? Or is there any other way to know which is the name of the form passed?

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-25T12:04:19+00:00Added an answer on May 25, 2026 at 12:04 pm

    Try this:

    echo "<form name='CLChange' method='post' action=''>";
    echo "<input type='hidden' name='userId' value='" . $userId . "' />";
    echo "<td><select name='NewClearanceLevel'>\n";
    for($i = 1; $i < $ClearanceLevel; $i++)
    {
        echo "<option value='" . $i . "'>" . $i . "\n";
    }
    echo"<input type='submit' value='Change'></td></form>";
    
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