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Home/ Questions/Q 7732833
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Editorial Team
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Editorial Team
Asked: June 1, 20262026-06-01T06:49:49+00:00 2026-06-01T06:49:49+00:00

I have the following php code that gets a serialized array from a mysql

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I have the following php code that gets a serialized array from a mysql database, then unserializes it. This is working fine. The following code:

$row=mysql_fetch_array($result);
$mydata=$row[0];
$unser=unserialize($mydata);

echo "$mydata<br>";
print_r($unser);
echo "<br>";
echo $unser[1901];

The output is this:

a:2:{i:2070;s:4:"0.00";i:1901;s:4:"1.00";}
Array ( [2070] => 0.00 [1901] => 1.00 ) 
1.00

So far, so good. Now, I’m trying to write the code so that it checks if the array key 1901 exists. For that, I tried this:

$search_array = $unser;
if (array_key_exists('1901', $search_array)) {
     echo "The key 1901 is in the array";
}

However that is returning an error. What am I doing wrong?

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  1. Editorial Team
    Editorial Team
    2026-06-01T06:49:50+00:00Added an answer on June 1, 2026 at 6:49 am

    With the following code:

    $mydata= 'a:2:{i:2070;s:4:"0.00";i:1901;s:4:"1.00";}';
    $unser=unserialize($mydata);
    
    echo "$mydata<br>";
    print_r($unser);
    echo "<br>";
    echo $unser['1901'];
    
    $search_array = $unser;
    if (array_key_exists('1901', $search_array)) {
         echo "<br />The key 1901 is in the array";
    }
    

    It will work correctly:

    a:2:{i:2070;s:4:"0.00";i:1901;s:4:"1.00";}
    Array ( [2070] => 0.00 [1901] => 1.00 )
    1.00
    The key 1901 is in the array
    

    Check if you have more code after the lines of code you have posted. I think is another piece of code which is confusing you.

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