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Home/ Questions/Q 6204469
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Editorial Team
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Editorial Team
Asked: May 24, 20262026-05-24T05:05:54+00:00 2026-05-24T05:05:54+00:00

I have the following piece of jQuery $(document).ready(function(){ var vH=$(‘#background’).height(); var vW=$(‘#background’).width(); var vT=$(‘#background’).offset().top;

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I have the following piece of jQuery

$(document).ready(function(){
        var vH=$('#background').height();
        var vW=$('#background').width();
        var vT=$('#background').offset().top;
        var vL=$('#background').offset().left;
        $('#test').mousemove(function(e){
            var ypos=e.pageY-vT;
            var xpos=e.pageX-vL;
            var y=Math.round(ypos/vW*1500);
            var x=Math.round(xpos/vH*200);
            $('#test').val(x+' , '+y);
            $('#background').css({backgroundPosition: x+'% '+y+'%'});
        });
    });

It moves the background when I move my mouse over the div with id=”test”. Now I want to change it so the background is moving no matter where you are moving the mouse over.

So is there a way to do this? Or is it possible to use multiple divs so you get something like:

$('#test', '#test2').mousemove(function(e){

I really appreciate your help!

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-24T05:05:56+00:00Added an answer on May 24, 2026 at 5:05 am

    Try this

    $(document).ready(function(){
            var vH=$('#background').height();
            var vW=$('#background').width();
            var vT=$('#background').offset().top;
            var vL=$('#background').offset().left;
            $(document).mousemove(function(e){
                var ypos=e.pageY-vT;
                var xpos=e.pageX-vL;
                var y=Math.round(ypos/vW*1500);
                var x=Math.round(xpos/vH*200);
                $('#test').val(x+' , '+y);
                $('#background').css({backgroundPosition: x+'% '+y+'%'});
            });
        });
    
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