Question

I have the following problem that needs to be solved in a MySQL query:

Fields
info - textfield
date1 - a date field
date2 - a date field
offset1 - a text field with a number in the first two positions, example "10-High"
offset2 - a text field with a number in the first two positions, example "10-High"

I need to sort the records by the calculated “sortvalue” based on the current date (today):

If today<date1 then sortvalue=offset1*10+offset2*5-1000
else if today>=date2 then sortvalue=offset1*10+offset2*5+1000
else sortvalue=offset1*10+offset2*5

I have quite good understanding of basic SQL with joins etc, but this I am not even sure if its possible…if it helps I could perhaps live with a single formula giving the same sort of effect as the IFs do….ie. before date1 = low value, after date2 = high value…

Rgds
PM

Answer 1

Use:

         ...
    FROM FIELDS t
ORDER BY CASE
           WHEN NOW() < t.date1 THEN CAST(LEFT(offset1, 2) AS INT) * 10 + CAST(LEFT(offset2, 2) AS INT) * 5 - 1000
           WHEN NOW() >= t.date2 THEN CAST(LEFT(offset1, 2) AS INT) * 10 + CAST(LEFT(offset2, 2) * 5 + 1000
           ELSE offset1 * 10 + offset2 * 5
         END