Question

I have the following program:

#include<stdio.h>
int main()
{
int i =257;
int *iptr =&i;
printf("%d%d",*((char*)iptr),*((char*)iptr+1));
return 0; 
}

The output is:

1 1

I am not able to understand why the second value is 1.
Please explain.

Answer 1

Because 257 in binary is 00000001 00000001: So both the first and the second bytes representing it are set to 1.

(char*)iptr is the char (thus 1 byte) pointed by iptr, and (char*)iptr+1 is the next byte.