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Home/ Questions/Q 8220511
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Editorial Team
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Editorial Team
Asked: June 7, 20262026-06-07T13:32:36+00:00 2026-06-07T13:32:36+00:00

I have the following python code. import sys ins = open( sys.argv[1], "r" )

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I have the following python code.

import sys

ins = open( sys.argv[1], "r" )
array = []
for line in ins:
    s = line.split()
    array.append( s[0] ) # <-- Error here 
print array

ins.close()

The python interpreter complains

  File "sort.py", line 7
    array.append( s[0] )
                       ^
IndentationError: unindent does not match any outer indentation level

Why so? And how to correct this error?

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-07T13:32:38+00:00Added an answer on June 7, 2026 at 1:32 pm

    You are mixing tabs and spaces (happens sometimes :). Use one or the other.

    I looked at your source:

        s = line.split()  # there's a tab at the start of the line
        array.append( s[0] )  # spaces at the start of the line
    

    Aside: As just a friendly suggestion, consider using with to open your file. The advantage is that the file will be automatically closed for you (no close() needed) when you are done or an exception is encountered.

    array = []
    with open( sys.argv[1], "r" ) as ins:  # "r" really not needed, it's the default.
       for line in ins:
          s = line.split()
          # etc...
    
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