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Home/ Questions/Q 7869813
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Editorial Team
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Editorial Team
Asked: June 3, 20262026-06-03T01:26:17+00:00 2026-06-03T01:26:17+00:00

I have the following query: $myquery = mysql_query(SELECT p.name, GROUP_CONCAT(m.name) as products FROM access

  • 0

I have the following query:

$myquery = mysql_query("SELECT p.name, GROUP_CONCAT(m.name) as products
                    FROM access as pm
                    INNER JOIN seller as p on p.id = pm.id_seller
                    INNER JOIN products as m on m.id  = pm.id_product
                    WHERE p.id = '".$_COOKIE['id_seller']."'");

Which returns me this array:

Array (
[0] => Seller Name [name] => Seller Name
[1] => Product1 [products] => Product1
);

How should I query the database correctly? Thanking in consideration that I have 3 tables (products, access and seller). What I’d like to achieve is to attribute (access) one or more products to a seller.

And how my drop-down list populate code would look like?

<?php
      echo'<select name="productaccess">';
foreach($myquery as $product) {
      echo'<option value="'.$product.'">'.$product.'</option>';
}
      echo'</select>';
?> 

Thanks!

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-03T01:26:19+00:00Added an answer on June 3, 2026 at 1:26 am

    If you want the products for just one seller, you don’t need grouping at all. Just list the names of the products:

    $myquery = mysql_query("SELECT m.name
                        FROM access as pm
                        INNER JOIN seller as p on p.id = pm.id_seller
                        INNER JOIN products as m on m.id  = pm.id_product
                        WHERE p.id = '".$_COOKIE['id_seller']."'");
    

    Now $myquery is only a resource identifier, not the results, so you get the latter with mysql_fetch_array() like this:

    while($row=mysql_fetch_array($myquery)) {
        echo'<option value="'.$row['name'].'">'.$row['name'].'</option>';
    }
    
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