Sign Up

Sign Up to our social questions and Answers Engine to ask questions, answer people’s questions, and connect with other people.

Have an account? Sign In

Have an account? Sign In Now

Sign In

Login to our social questions & Answers Engine to ask questions answer people’s questions & connect with other people.

Sign Up Here

Forgot Password?

Don't have account, Sign Up Here

Forgot Password

Lost your password? Please enter your email address. You will receive a link and will create a new password via email.

Have an account? Sign In Now

You must login to ask a question.

Forgot Password?

Need An Account, Sign Up Here

Please briefly explain why you feel this question should be reported.

Please briefly explain why you feel this answer should be reported.

Please briefly explain why you feel this user should be reported.

Sign InSign Up

The Archive Base

The Archive Base Logo The Archive Base Logo

The Archive Base Navigation

  • SEARCH
  • Home
  • About Us
  • Blog
  • Contact Us
Search
Ask A Question

Mobile menu

Close
Ask a Question
  • Home
  • Add group
  • Groups page
  • Feed
  • User Profile
  • Communities
  • Questions
    • New Questions
    • Trending Questions
    • Must read Questions
    • Hot Questions
  • Polls
  • Tags
  • Badges
  • Buy Points
  • Users
  • Help
  • Buy Theme
  • SEARCH
Home/ Questions/Q 3958186
In Process

The Archive Base Latest Questions

Editorial Team
  • 0
Editorial Team
Asked: May 20, 20262026-05-20T02:34:50+00:00 2026-05-20T02:34:50+00:00

I have the following query SELECT interview_content.title `title`, gallery_images.img_path img FROM `interview`, `interview_content`, `gallery`,

  • 0

I have the following query

SELECT
    interview_content.title `title`,
    gallery_images.img_path img
FROM
    `interview`,
    `interview_content`,
    `gallery`,
    `gallery_images`
WHERE
    `gallery_images`.`id_parrent` = `gallery`.`id`
AND
    `gallery`.`id` =  `interview`.`gallery_id`
AND
    `gallery_images`.`default` = '1'
AND
    `interview`.`id` = `interview_content`.`id_parrent`
AND
    interview_content.id_lang = '2'
ORDER BY
    interview.date DESC

I need to use LEFT JOIN on gallery, gallery_images tables (to be able to get interview.title even when there is no gallery or default image)

Thanks much

UPDATE


The problem, is in second LEFT JOIN. I can’t make them to work together correctly. When i try

SELECT
    interview_content.title `title`,
    gi.img_path img
FROM
    `interview`,
    `interview_content`
LEFT JOIN `gallery` as g ON g.`id` = `interview`.`gallery_id` 
LEFT JOIN `gallery_images` as gi ON gi.id_parrent = g.`id`
WHERE
    `interview`.`id` = `interview_content`.`id_parrent`
AND
    interview_content.id_lang = '2'
ORDER BY
    interview.date DESC

it returns //Unknown column 'interview.gallery_id' in 'on clause'
  • 1 1 Answer
  • 0 Views
  • 0 Followers
  • 0
Share
  • Facebook
  • Report

Leave an answer
Cancel reply

You must login to add an answer.

Forgot Password?

Need An Account, Sign Up Here

1 Answer

  • Voted
  • Oldest
  • Recent
  • Random
  1. Editorial Team
    Editorial Team
    2026-05-20T02:34:50+00:00Added an answer on May 20, 2026 at 2:34 am

    Don’t mix ANSI-89 style and ANSI-92 style joins.

    I found same question in SO, here.

    So my query must look like this

    SELECT
        ic.title `title`,
        gi.img_path img
    FROM
        `interview` i
    JOIN interview_content ic  on ic.id_parrent =  i.id AND ic.id_lang = '2'
    LEFT JOIN `gallery` as g ON g.`id` = i.`gallery_id` 
    LEFT JOIN `gallery_images` as gi ON gi.id_parrent = g.`id`
    AND gi.`default` = '1'
    WHERE
        i.`id` = ic.`id_parrent`
    OPRDER BY
        `i`.`date` DESC
    
    • 0
    • Reply
    • Share
      Share
      • Share on Facebook
      • Share on Twitter
      • Share on LinkedIn
      • Share on WhatsApp
      • Report

Sidebar

Related Questions

I have the following query: SELECT title, karma, DATE(date_uploaded) as d FROM image ORDER
I have the following query: select column_name, count(column_name) from table group by column_name having
I have the following query: SELECT c.* FROM companies AS c JOIN users AS
I have the following query: SELECT rowid FROM table1 ORDER BY RANDOM() LIMIT 1
I have the following query SELECT e.topicShortName, d.catalogFileID, e.topicID FROM catalog_topics a LEFT JOIN
I have the following query: SELECT COUNT(*) FROM FirstTable ft INNER JOIN SecondTable st
I have the following query: SELECT o.id,o.name FROM object o WHERE ( o.description LIKE
I have the following query SELECT * FROM attend RIGHT OUTER JOIN noattend ON
I have the following query: SELECT DISTINCT w.name, count(*) FROM widgets AS w JOIN
Suppose I have the following query: select * from A, B, C, D where

Explore

  • Home
  • Add group
  • Groups page
  • Communities
  • Questions
    • New Questions
    • Trending Questions
    • Must read Questions
    • Hot Questions
  • Polls
  • Tags
  • Badges
  • Users
  • Help
  • SEARCH

Footer

© 2021 The Archive Base. All Rights Reserved
With Love by The Archive Base

Insert/edit link

Enter the destination URL

Or link to existing content

    No search term specified. Showing recent items. Search or use up and down arrow keys to select an item.